Answer:
[see below]
Step-by-step explanation:
In the provided screenshot, the value of r is 2.5.
We would replace 'r' with 2.5 and then make 's' the subject of the equation.
[tex]2r + 3s = 14\\\rule{150}{0.5}\\2(2.5) + 3s = 14 \leftarrow \text {This would go in the first blank.}\\\\5 + 3s = 14 \leftarrow \text {This would go in the second blank.}\\\\3s + 5 = 14\\\\3s + 5 - 5 = 14 - 5\\\\3s = 9 \leftarrow \text {This would go in the third blank.}\\\\\frac{3s=9}{3}\\\\\boxed{s = 3} \leftarrow \text {This would go in the fourth blank.}[/tex]
Hope this helps you.
