If you need to multiply the following reaction by 2 to be an intermediate
reaction in a Hess's law problem, what would be the final value for the
enthalpy of reaction you use for this intermediate reaction? C2H4 +3 02-2
CO2 + 2 H20, AH = -1410 kJ
A. 2820 kJ
B. -1410 kJ
C. -2820 kJ
D. 1410 kJ
PLEASE HELP ITS DUE TONIGHT

Respuesta :

Answer:

-2820 kJ

Explanation:

Just got it right on Ap3x :)

Check your question and verify that it says "multiply" and not "reverse", this is the only page that has the answer for that one.

If you have "reverse" there is another guy who asked the question, is easy to find.

Considering the definition of extensive properties and heat of reaction, the enthalpy of reaction for the intermediate reaction is -2820 kJ (option C.).

Extensive property

Extensive properties of matter are defined as those that depend on the amount of material in a body.

The greater the mass or the larger the body or system, the greater the proportion of that property. This means that extensive properties are not fixed, they vary according to the amount of matter.

Also, extensive properties are additive, meaning they can be added together.

Enthalpy or heat of reaction

The heat of reaction is the energy that is released or absorbed when chemicals are changed in a chemical reaction.

Enthalpy is an extensive property: its magnitude depends on the amount of matter present.

Enthalpy of reaction for the intermediate reaction

Since enthalpy is an extensive property, if you need to multiply the following reaction by 2 to be an intermediate reaction in a Hess's law problem, the variation of enthalpy also is pultiplied by 2.

Then, ΔH= 2×( -1410 kJ)

ΔH= -2820 kJ

Finally, the enthalpy of reaction for the intermediate reaction is -2820 kJ (option C.).

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