Respuesta :
The heat required to convert -45 degrees Celsius ice to 0 degree Celsius ice has been 0.9450 kJ.
Heat required to convert 0 degree Celsius ice to 0 degree Celsius water has been 0 kJ.
The heat required to convert 0 degrees Celsius water to 75 degree Celsius water has been 31.5 kJ.
The sample of water at -45 degree Celsius has been converted to 75 degree Celsius in the following steps:
- -45 degrees Celsius ice to 0 degree Celsius ice
- 0 degree Celsius ice to 0 degree Celsius water
- 0 degree Celsius water to 75 degree Celsius water
The heat required for the conversion has been given as:
[tex]\rm Heat=mass\;\times\;specific heat\;\times\;change\;in\;temperature[/tex]
Computation for the heat required
The mass of sample has been 0.1 kg.
- Heat required to convert -45 degrees Celsius ice to 0 degree Celsius ice has been:
It has been known that the Specific heat of ice has been [tex]\rm 2100\;JKg^-^1K^-^1[/tex]
Substituting the values:
[tex]\rm Heat=0.1\;\times\;2100\;\times\;(273.15-228.15)\\Heat=0.1\;\times\;2100\;\times\;45\\Heat=9,450\;J[/tex]
The heat required to convert -45 degrees Celsius ice to 0 degree Celsius ice has been 0.9450 kJ.
- Heat required to convert 0 degree Celsius ice to 0 degree Celsius water has been 0 as there has been no change in temperature.
- Heat required to convert 0 degree Celsius water to 75 degree Celsius water has been:
It has been known that the Specific heat of water has been [tex]\rm 4200\;JKg^-^1K^-^1[/tex].
Substituting the values:
[tex]\rm Heat=0.1\;\times\;4200\;\times\;(348.15-273.15)\\Heat=0.1\;\times\;4200\;\times\;75\\Heat=31,500\;J[/tex]
The heat required to convert 0 degrees Celsius water to 75 degree Celsius water has been 31.5 kJ.
Learn more about heat required, here:
https://brainly.com/question/13803348
Answer:
q1 = 9.42 kJ
q2 = 226 kJ
q3 = 31.4 kJ
qtot = 267 kJ
Explanation:
I Did This On Edge And This Was Correct ;)
