Use the periodic table to calculate the molar mass of each of the following compounds. Each answer must have 2 decimal places. Ammonia (NH3): g/mol Magnesium hydroxide (Mg(OH)2): g/mol Iron(III) oxide (Fe2O3): g/mol.

Respuesta :

The molar mass of ammonia has been 17.03 g/mol. The molar mass of magnesium hydroxide has been 41.31 g/mol. The molar mass of Iron oxide has been 159.67 g/mol.

The periodic table has been the arrangement of the elements in the increasing order of the atomic number and similarity in the chemical properties.

Molar mass

Molar mass has been the sum of mass of each atom in a formula unit. The molar mass of the following compounds has been:

  • Ammonia ([tex]\rm NH_3[/tex])

The molar mass has been, mwt

[tex]mwt=\rm Mass\;N\;+\;3\;\times\;Mass\;H\\\textit{mwt}=14.006\;+\;3\;\times\;1.007\\\textit{mwt}=17.03\;g/mol[/tex]

The molar mass of ammonia has been 17.03 g/mol.

  • Magnesium hydroxide ([tex]\rm Mg(OH)_2[/tex])

The molar mass has been, mwt

[tex]mwt=\rm Mass\;Mg\;+\;2\;\times\;Mass\;O\;+\;2\;\times\;Mass\;H\\\textit{mwt}=24.305\;+\;2\;\times\;1.007\;+\;2\;times\;15.994\\\textit{mwt}=41.31\;g/mol[/tex]

The molar mass of magnesium hydroxide has been 41.31 g/mol.

  • Iron oxide ([tex]\rm Fe_2O_3[/tex])

The molar mass has been, mwt

[tex]mwt=\rm 2\;\times\;Mass\;Fe\;+\;3\;\times\;Mass\;O\\\textit{mwt}=2\;\times\;55.845\;+\;3\;\times\;15.994\\\textit{mwt}=159.67\;g/mol[/tex]

The molar mass of Iron oxide has been 159.67 g/mol.

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