Respuesta :
A parallelogram is a flat shape with opposite sides parallel and equal in length. The diagonals of a parallelogram bisect each other. In simpler words, they intersect halfway point. We calculate as follows:
d2 = √2a^2 + 2b^2 - d1^2
d2 = √2(7)^2 + 2(9)^2 - 14^2
d2 = 8 inches
d2 = √2a^2 + 2b^2 - d1^2
d2 = √2(7)^2 + 2(9)^2 - 14^2
d2 = 8 inches
Answer:
the length of the other diagonal is ≈ 8
Step-by-step explanation:
Given that:
- one side 7 inches
- one side 9 inches
- diagonal is 14 inches
we can use the law of cosines to find out the angle that formed by the 7 inch side and 9 inch side (please have a look at the attached photo)
Let say ∠ABC, we have:
[tex]c^{2} =a^{2} +b^{2} -2abcos(B)\\[/tex]
<=> [tex]14^{2} =7^{2} +9^{2} -2*7*9cos(B)\\[/tex]
<=> cos(B) = -11/21
<=> ∠ABC = 121 degrees.
From the properties of parallelograms, we know that the sum of the 4 inter angles is 360 degrees.
2∠ABC + 2∠BAC =360
<=> ∠BAC = (360 - 2∠ABC) /2
<=> ∠BAC = (360 - 2*121) /2
<=> ∠BAC =59 degrees
Once again, we use can use the law of cosines to find out the length of the shorter diagonal
[tex]d^{2} =a^{2} +b^{2} -2abcos(A)\\[/tex]
= [tex]7^{2} +9^{2} -2*7*9cos(59)\\[/tex]
= 65
<=> d = [tex]\sqrt{65}[/tex] ≈ 8
