Respuesta :

Answer:

[tex] x = -4 + \sqrt{7} [/tex]  and  [tex] x = -4 - \sqrt{7} [/tex]

Step-by-step explanation:

The x-intercepts occur at y = 0.

0 = (x + 4)² - 7

x² + 8x + 16 - 7 = 0

x² + 8x + 9 = 0

[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]

[tex] x = \dfrac{-8 \pm \sqrt{8^2 - 4(1)(9)}}{2(1)} [/tex]

[tex] x = \dfrac{-8 \pm \sqrt{64 - 36}}{2} [/tex]

[tex] x = \dfrac{-8 \pm \sqrt{28}}{2} [/tex]

[tex] x = \dfrac{-8 \pm 2\sqrt{7}}{2} [/tex]

[tex] x = -4 \pm \sqrt{7} [/tex]

[tex] x = -4 + \sqrt{7} [/tex]  and  [tex] x = -4 - \sqrt{7} [/tex]

Answer:

  • (- 4 + 7, - 4 - 7)

Step-by-step explanation:

Given equation:

  • y = (x + 4)² - 7

Find its x-intercepts, the values of x when y = 0:

  • (x + 4)² - 7 = 0
  • (x + 4)² = 7
  • x + 4 = ± 7
  • x = - 4 ± 7