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A sample of potassium nitrate, kno3, (49. 0 g) is dissolved in 100 g of water at 100 °c with precautions taken to avoid evaporation of any water. The solution is slowly cooled to 30. 0 °c and a small amount of precipitate is observed. The solution at 30. 0 °c is.

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The solution at 30. 0 °c is a saturated solution.

What is a Solution?

In chemical analysis, a solution is a homogeneous combination of two or more substances(usually a solute and solvent) in relative proportions that may be adjusted continuously(commonly referred to as solubility limit).

From the parameters given:

  • A sample of potassium nitrate KNO3 = 49.0 g

From the solubility curve, we need to know that:

  • Solubility of KNO3 at 25°C = 24 g in 100 mL of water
  • Solubility of KNO3 at 100°C = 245g in 100 mL of water

Now, if 49 grams of KNO3 was dissolved in 100g at 25° C. It implies that 24 g of KNO3 will dissolve and it will remain 25 g KNO3 as undissolved(solid) at the bottom. This phenomenon can be termed as a saturated solution.

However, the remaining 25 g of KNO3 was heated to 100° C, the remaining 25 grams of KNO3 will also dissolve. Here, the temperature at the solubility limit in 100 mL of water at 244 g makes this to be an unsaturated solution.

Now, if the solution is slowly cooled back to 30.0° C, 25 grams of the KNO3 is supposed to precipitate from the solution making it become a saturated solution once again.

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