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A pressure washer uses a high-velocity jet of water to clean surfaces. Every second, 17.0kg of water is expelled at a velocity of 24.0m⋅s−1. What is the magnitude of the force from the water onto a surface? Assume that the water velocity is reduced to zero when it hits a surface. Give your answer in Newtons, correct to three significant figures, without a unit.

Respuesta :

hamzaahmeds

This question involves the concepts of Newton's Second Law of Motion and Momentum.

The magnitude of the force from the water onto the surface is "408".

According to

Newton's Second Law of Motion:

[tex]F=\frac{\Delta P}{t}[/tex]

where,

  • F = Force = ?
  • ΔP = Change in Momentum = [tex]m(v_f-v_i)[/tex]
  • t = time interval = 1 s
  • m = mass = 17 kg
  • vf = final speed = 0 m/s
  • vi = initial speed = 24 m/s

Therefore,

[tex]F=\frac{\Delta P}{t}=\frac{m(v_f-v_i)}{t}\\\\F=\frac{(17\ kg)(0\ m/s-24\ m/s)}{1\ s}\\\\F=-408 N[/tex]

The negative sign shows reaction force.

F = 408

Learn more about Newton's Second Law of Motion here:

https://brainly.com/question/23845187

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