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2d. In the partially shown sequence: …, 17711, a, b, 75025, …, each new term is the sum of the two previous terms. Find the whole number value of a.

Respuesta :

The whole number value of a for the given sequence is; 28657

Arithmetic Sequence

We are given the partial sequence as;

…, 17711, a, b, 75025, …,

Now, we are told that each new term is the sum of the two previous terms. Thus;

  • 17711 + a = b  ----(eq 1)
  • a + b = 75025  ----(eq 2)

Put 17711 + a for b in eq 2 to get;

a + 17711 + a = 75025

2a + 17711 = 75025

2a = 75025 - 17711

2a = 57314

a = 57314/2

a = 28657

Read more on Arithmetic Sequence at; https://brainly.com/question/7882626

dharrithul

Answer:

Explanation:

We are given the partial sequence as;

…, 17711, a, b, 75025, …,

Now, we are told that each new term is the sum of the two previous terms. Thus;

17711 + a = b  ----(eq 1)

a + b = 75025  ----(eq 2)

Put 17711 + a for b in eq 2 to get;

a + 17711 + a = 75025

2a + 17711 = 75025

2a = 75025 - 17711

2a = 57314

a = 57314/2

a = 28657