Aquimedes' principle allows to find the result for the apparent weight of the steel sphere is:
The thrust of a fluid on a body is given by Archimedes' principle which states that equal to the weight of the displaced liquid.
B = [tex]\rho \ g \ V_{liquid}[/tex]
Where B is the buoyancy, p the density of the liquid, g the acceleration due to gravity and V the volume of the liquid.
In the attachment we see a free body diagram of the system, which is a representation of the forces without the details of the bodies.
[tex]W_{apparent}[/tex] = W- B
The volume of the liquid is the same as the volume of the sphere.
[tex]V_{liquid} = V_{body} = \frac{4}{3} \pi r^3[/tex]
Let's substitute.
[tex]W_{apparent} = m g - \rho_{liquid} \ g \ (\frac{4}{3} \pi r^3 )[/tex]
Let's calculate.
[tex]W_{apparent} = 9.8 ( 38 - \frac{4}{3} \pi \ 1000 \ 0.04^3 ) = 9.8 \ 37.73[/tex]
.[tex]W_{apparent} = 369.77 N[/tex]
In conclusion, using Aquimedes' principle, we can find the result for the apparent weight of the steel sphere:
Learn more about Archimedes' principle here: brainly.com/question/13106989
