A marksman holds a rifle of mass 3 kg loosely, so it can recoil freely. He fires a bullet of mass 5 g horizontally with a velocity relative to the ground of 300 m/s. What is the recoil velocity of the rifle?.

Respuesta :

The recoil velocity of the rifle is 0.5 m/s

Law of conservation of momentum

Using the law of conservation of momentum, the momentum of the bullet, M equals the momentum of the rifle, M'

M = M'

mv = m'V where m = mass of bullet = 5 g = 0.005 kg, v = velocity of bullet = 300 m/s, m' = mass of rifle = 3 kg and V = recoil velocity of rifle

Finding the recoil velocity of the rifle

Making V subject of the formula, we have

V = mv/m'

Substituting the values of the variables into the equation, we have

V = mv/m'

V = 0.005 kg × 300 m/s ÷ 3 kg

V = 0.005 × 100 m/s

V = 0.5 m/s

So, the recoil velocity of the rifle is 0.5 m/s

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