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Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter of solution,what is the molarity of H+?
Answer in units of M doing mole/liter doesn't work

Respuesta :

yashddsy26
as, using formula.........0.054/(.667/18)
=.o54/.037
=1.45 approx

so the answer
The answer is 0.612M

Find the molarity of the diprotic acid.
667ml ÷ 1000ml = 0.667L
M = 0.054 ÷ 0.667 = 0.08095952023 = 0.081 M H2SO4
There are 2 H+ for every one H2SO4, so the molarity of H+ is twice the molarity of the acid.
2 x 0.081M = 0.162M

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