Data:
P = 1 atm
V = 5.20 L
n = ?
R = 0.082 for pressures in atmosphere (atm)
T = 136ºC
The temperature to be used in the equation will always be in Kelvim (K), so if it is in degrees Celsius (° C) it is necessary to convert. To do this simply add the value 273.
TK = TºC + 273
TK = 136 + 273
TK = 409
Formula: (General Equation of Perfect Gases)
P*V = n*R*T
1*5.20 = n*0.082*409
5.20 = 33.538n
33.538n = 5.20
[tex] n = \frac{5.20}{33.538} [/tex]
[tex]\boxed{n \approx 0.15mol}[/tex] of nitrogen molecules
Note: One mole is the amount of matter in a material system containing [tex]6,02*10^{23}[/tex] particles (elemental entities).
Therefore:
Number atoms in 1 mol of molecules of N2 = 6.02*10²³ * 2 = 12.04*10²³
1mol ---------------- 12,04*10²³
0.15 mol ---------------- x
x = 0.15 * 12,04*10²³
x ≈ 1.8*10²³ atoms in 1 mole of N2 molecules.
