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MissPhiladelphia
Gravity changes as the altitude change. The gravitational force is proportional to 1/R2,  where R is the distance from the center of the Earth the radius of earth where gravity is 9.8 m/s^2 is 6400 km this will serve as the zero mark.

g1/(g2) = R2^2/(R1)^2

so we set the constant values to R1 and the unknown distance as x

(9.8)/(8.80) = (6400-x)2/(6400)^2

solving for x we will get 

x = 345.85 km above the earths surface

Hope my answer would be a great help for you.    
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Answer:

[tex]355.8km[/tex]

Explanation:

We use the equation to calculate gravitational acceleration [tex]g[/tex]

[tex]g=\frac{GM}{r^2}[/tex]

where  is the universal gravitational constant [tex]G=6.67x10^{-11}m^3/kgs^2[/tex], [tex]M[/tex] is the mass of the earth: [tex]M=5.97x10^{24}kg[/tex], and [tex]r[/tex] is the radius from the center of earth.

Clearing for the distance r:

[tex]r=\sqrt{\frac{GM}{g} }[/tex]

substituting known values

[tex]r=\sqrt{\frac{(6.67x10^{-11}m^3/kgs^2)(5.97x10^{24}kg)}{8.80m/s^2} }[/tex]

[tex]r=\sqrt{\frac{3.982^{14}m^3/s^2}{8.80m/s^2} }[/tex]

[tex]r=\sqrt{4.525x10^{13}m^2 }[/tex]

[tex]r=6.7268x10^6m[/tex]

and since the radius of earth from the core to the surface is about [tex]6.371x10^6m[/tex], the distance above the surface where g is reduce to [tex]8.80m/s^2[/tex]  is:

[tex]r=6.7268x10^6m-6.371x10^6m=355,800m[/tex] wich in kilometers is: [tex]355.8km[/tex]

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