Respuesta :
(2x²+7x-3)/(2x+5)=(2x²+5x+2x-3)/(2x+5)
=x(2x+5)/(2x+5)+ (2x+5-5-3)/(2x+5)
=(x+1)/(2x+5)-8/(2x+5)
==> 2x²+7x-3=(x+1)(2x+5)-8
Quotient=x+1 remainder=-8
=x(2x+5)/(2x+5)+ (2x+5-5-3)/(2x+5)
=(x+1)/(2x+5)-8/(2x+5)
==> 2x²+7x-3=(x+1)(2x+5)-8
Quotient=x+1 remainder=-8
Answer:
x+1 and remainder is -8
Step-by-step explanation:
Given that an algebraic expression
[tex]2x^2+7x-3[/tex] is divided by [tex]2x+5[/tex]
We have to find the quotient and remainder.
[tex]2x+5) 2x^2+7x-3(x+1\\\\ 2x^2+5x\\ --------------\\ 2x-3\\\\ 2x+5\\ ----------------\\ -8 =R[/tex]
Quotient is x+1 and remainder is -8
