Answer:
The probability is:
1/6, 497, 400
Step-by-step explanation:
We are given that:
We pick 4 cards randomly from a well-shuffled standard deck of 52 playing cards.
We are asked to find the probability such that:
We draw 2, 4, 6, and 8 of spades in that order.
i.e. firstly we have to draw a 2 of a spade.
at second turn we have to draw a 4 of a spade.
at third turn we have to draw a 6 of a spade.
at the last draw we have to draw 8 of a spade.
As there are total 52 cards.
The probability of drawing a 2 of a spade at first turn= 1/52.
The probability of drawing a 4 of a spade at second turn= 1/51.
( since 1 card has been drawn out in the first turn).
The probability of drawing a 6 of a spade at third turn= 1/50.
The probability of drawing a 8 of a spade at fourth turn= 1/49
Hence, the total probability that you draw the 2, 4, 6, and 8 of spades in that order is :
[tex]=\dfrac{1}{52}\times \dfrac{1}{51}\times \dfrac{1}{50}\times \dfrac{1}{49}\\ \\\\=\dfrac{1}{6497400}[/tex]
