Data:
[tex] E_{ep} = ?[/tex] (The SI unit of potential energy is the joule)
[tex]k = 53 N/m[/tex]
[tex]x = 0,21m[/tex] → [tex]x = 2,1 * 10^{-1}m [/tex]
Formula:
[tex] E_{ep} = \frac{k*x^2}{2} [/tex]
Solving:
[tex] E_{ep} = \frac{k*x^2}{2} [/tex]
[tex]E_{ep} = \frac{53*(2,1 * 10^{-1})^2}{2}[/tex]
[tex]E_{ep} = \frac{53*4,41 * 100^{-1}}{2}[/tex]
[tex]E_{ep} = \frac{233,73 * \frac{1}{100} }{2}[/tex]
[tex]E_{ep} = \frac{ \frac{233,73}{100} }{2}[/tex]
[tex]E_{ep} = \frac{ {2.3373} }{2}[/tex]
[tex] \boxed{E_{ep} = 1.16865J}[/tex]
