Respuesta :
Since H2O is excess, C is limiting reagent and it will decide the amount of H2 formed. Moles of C = 34/12.01 = 2.83. According to stoichiometry, moles of C = moles of H2. Therefore, moles of H2 = 2.83. Mass of H2 formed = moles of H2 formed x molar mass of H2 = 2.83 x 2.016 = 5.70528 grams.
Answer:
Correct dimensional analysis is below.
Explanation:
34g 1 mole c 1 mole H2 2.016g H2
___ x ________ x ________ x _________
12.01g C 1 mole c 1 mole H2
Hope this helps.