Respuesta :
Answer:
Given Function is,
[tex]P(x) = -x^4 + x^3 + 7x^2 - x - 6[/tex]
Which is the bi quadratic function.
For x-intercept, P(x)=0
Thus, [tex] -x^4 + x^3 + 7x^2 - x - 6=0[/tex]
⇒ [tex](x-1) ( -x^3+7x+6)=0[/tex]
⇒ [tex](x-1) (x+1) (x+2) (x-3) = 0[/tex]
⇒ The x-intercept of the functions are, (-2,0), (-1,0), (1,0) and ( 3,0)
Similarly, for y-intercept,
x = 0 , y = -6
Thus, y-intercept of the given function is, (0,-6)
The critical points of the function f(x) are ( where f'(x) = 0), (2.254, 12.949)
and (-1.574, 2.879)
End Behavior:
Since, The leading coefficient is negative and has even degree,
Therefore, end behavior of the given function is,
[tex]f(x)\rightarrow -\infty[/tex] as [tex]x\rightarrow -\infty[/tex]
And, [tex]f(x)\rightarrow -\infty[/tex] as [tex]x\rightarrow +\infty[/tex]
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Answer:look
Step-by-step explanation:
First, lets find the zeros.
-x4 + x3 + 7x2 - x - 6 = 0
Using synthetic division, the left side factors to
(x - 3)(-x3 - 2x2 + x + 2) = 0
Then by group factoring the second factor,
(x - 3)[-x3 + x - 2x2 + 2] = 0
(x - 3)[-x(x2 - 1) - 2(x2 - 1)] = 0
(x - 3)(x2 - 1)(-x - 2) = 0
(x - 3)(x - 1)(x + 1)(-x - 2) = 0
Our zeros are then
x = -2
x = -1
x = 1
x = 3
The company will break even when 1 tree is cut down or 3 trees are cut down.
Since we have a negative 4th degree function, the graph will start off increasing, and then end off decreasing. This is a symmetrical function. Using this fact, we know can tell the shape the graph. It will have 2 maximums and 1 minimum. There is a maximum in the interval (-2, -1), a minimum in the interval (-1, 1), and another maximum in the interval (1, 3). This is in the general sense of the graph.
However, the number of trees must be positive. So the company makes a minimum profit when they don't cut down any trees. The company makes a maximum profit when 2 trees are cut down. When no trees are cut down, the company loses profit by 6.
As for the end behaviors, x cannot be negative because you cannot cut down negative number of trees. Therefore, the graph starts at x=0.
The profits start to increase when at most 2 trees are cut down.
After 2 trees are cut down, the profits decrease.