Respuesta :

7x+21                 x+6
...............   ÷  .................
x^2+5x+6          x+2

= 7 (x+3)        ÷      x + 6
...............           ...................
(x+3)(x+2)              x+2

= 7 (x+3)        *       x + 2
...............           ...................
(x+3)(x+2)              x + 6

=  7
--------
 x + 6

Answer:

[tex]\frac{7}{(x+6)}[/tex]

Step-by-step explanation:

Simplify: 7x+21/x^2+5x+6 divided by x+6/x+2

[tex]\frac{7x+21}{x^2+5x+6} divide \ by \frac{x+6}{x+2}[/tex]

WE change the division by multiplication then we flip the second fraction

[tex]\frac{7x+21}{x^2+5x+6} * \frac{x+2}{x+6}[/tex]

Now we factor the expression x^2 + 5x+6

x^2 + 5x +6 becomes (x+3)(x+2)

now factor 7x +21 , it becomes 7(x+3)

[tex]\frac{7(x+3)}{(x+3)(x+2)} * \frac{x+2}{x+6}[/tex]

Cancel out x+3 at the top and bottom

Also cancel out x+2

so the given expression becomes

[tex]\frac{7}{(x+6)}[/tex]

Otras preguntas