Respuesta :
Answer : The kinetic energy of the box is, 80 J
Explanation :
The formula used for kinetic energy is:
[tex]K.E=\frac{1}{2}mv^2[/tex]
where,
K.E = kinetic energy = ?
m = mass = 40 kg
v = velocity = 2 m/s
Now put all the given values in the above formula, we get the kinetic energy of the box while it is on the conveyor belt.
[tex]K.E=\frac{1}{2}mv^2[/tex]
[tex]K.E=\frac{1}{2}\times (40kg)\times (2m/s)^2[/tex]
[tex]K.E=80kg.m^2/s^2=80J[/tex]
Thus, the kinetic energy of the box is, 80 J
The kinetic energy of the box on the conveyer belt is 80 J.
How do you calculate the kinetic energy?
Given that the mass m of the box is 40 kg and velocity v is 2 m/s.
The kinetic energy of the box can be calculated as given below.
[tex]KE = \dfrac {1}{2} mv^2[/tex]
Substituting the values of mass and velocity.
[tex]KE = \dfrac {1}{2}\times 40\times 2^2[/tex]
[tex]KE = 80 \;\rm J[/tex]
Hence we can conclude that the kinetic energy of the box is 80 J.
To know more about kinetic energy, follow the link given below.
https://brainly.com/question/999862.
