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Which circuit diagram represents voltmeter V connected correctly to measure the potential difference across resistor R2?

Which circuit diagram represents voltmeter V connected correctly to measure the potential difference across resistor R2 class=

Respuesta :

The "V" should be inside of the circle on the diagram - that's why we'll exclude the option (3) where it isn't.

Also, we want to measure only R2, so we're looking for an option where R1 and R2 are separated - that's only 3 and 4..

But, since we before rejected option (3), we're left with 4 -this is the correct answer!

Among all the option available none can measure the potential difference for resistor [tex]\bold {R_2}[/tex].

What is a voltmeter?

A voltmeter is a device used to measure the potential difference between two points in a circuit. The voltmeter is connected in parallel with the element to be measured, therefore, an alternate current path around the element to be measured and through the voltmeter is created.

How to use a voltmeter?

The correct way to know whether the voltmeter is placed at the right place is if you can remove the voltmeter from the circuit without breaking the circuit. Hence, In order to calculate the potential difference for any element in the circuit, the voltmeter must be connected in parallel.

Which circuit diagram is correct?

Although the only option that looks feasible is option (3) where the voltmeter is connected to [tex]\bold {R_2}[/tex] in a parallel connection but as the "V" is not in the circle we have to reject the option.

Among the rest, the only option in which the voltmeter connected in the parallel is option 2, but in option 2 the voltmeter will measure the potential difference of the complete circuit including [tex]\bold {R_1}[/tex] and [tex]\bold {R_2}[/tex].

Also, for option 1 and option 4 the voltmeter is connected in series which will not give us the correct potential difference because if the voltmeter is connected in series then due to high resistance no current will flow through the circuit. so, no voltage drop will occur.

Hence, among all the option available none can measure the potential difference for resistor [tex]\bold {R_2}[/tex].

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