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A vehicle of mass 1600kg take off from rest and coveres a distance of 280m in 60s. It continues at this speed for 98seconds and comes to rest after 106s. i. Determine the total distance covered. ii. Determine the amount of force exerted as it slow to a stop. iii. If the road is inclined at 30degrees to the horizontal,what is the horizontal component of its velocity?

Respuesta :

1. V = Vo + a*t. 
15 = 0 + a*5 a = 3 m/s^2. 

2. V = Vo + a*t. 
0 = 15 - 5*t, t = 3 s. 

3. d1 = Vo*t + 0.5a*t^2. 
Vo = 0, t = 5, a = 3 m/s^2, d1 = ?. 

d2 = Vo*t. Vo = 15 m/s, t = 15 s, 
d2 = ?. 

V^2 = Vo^2 + 2a*d3. 
V = 0, Vo = 15 m/s, a = -5 m/s^2, d3 = ?. 

d1+d2+d3 = Total dist.

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