Evaluate using substitution ∫(2x^5+6x)^3(5x^4+3)dx where b=0 and a=-1
I got to here and then got stuck u=5x^4+3 du=x^5+3x+C ∫(2x^5+6x)^3 u 1/(x^5+3x+C) ∫(x^5+3x)^3 u