The base of a pyramid covers an area of 13.0 acres (1 acre = 43,560 ft2) and has a height of 481 ft. If the volume of a pyramid is given by the expression V = (1/3)bh, where b is the area of the base and h is the height, find the volume of this pyramid in cubic meters.

Respuesta :

Answer:

2570987.31 m³

Explanation:

Base area = 13 acres = b

Converting to ft²

1 acre = 43,560 ft²

⇒13 acre = 566280 ft²

Height of pyramid = 481 ft = h

Volume

[tex]v=\frac{1}{3}bh\\\Rightarrow v=\frac{1}{3}566280\times 481\\\Rightarrow v=90793560\ ft^3[/tex]

Converting to cubic meters

1 ft = 0.3048 m

⇒1 ft³ = 0.3048×0.3048×0.3048 m³

⇒1 ft³ =  0.3048³ m³

90793560 ft³ = 90793560×0.3048³

⇒90793560 ft³ = 2570987.31 m³

∴ Volume of this pyramid is 2570987.31 m³

Explanation:

Given that,

The area of the base of a pyramid, b = 43,560 ft²

The height of the pyramid, h = 481 ft

To find,

The volume of the pyramid.

Solution,

We know that,

1 ft = 0.3048 m

b = 4046.85 m² and h = 146.609 m

The volume of a pyramid is given by :

[tex]V=\dfrac{1}{3}bh[/tex]

Put all the values,

[tex]V=\dfrac{1}{3}\times 4046.85\times 146.609\\\\V=197768.21\ m^3[/tex]

Answer:

The volume of the pyramid is [tex]197768.21\ \text{feet}^3[/tex].

Reference:

https://brainly.com/question/12630013