Answer: E
Step-by-step explanation:
In Parallelogram ABCD and EFGH ,
∠A, ∠B, ∠C and ∠D are corresponding to ∠E, ∠F, ∠G and ∠H respectively.
Since, According to the given question,
parallelogram ABCD is dilated to form parallelogram EFGH,
Therefore, By the property of dilation,
Parallelogram ABCD is similar to parallelogram EFGH,
⇒ ∠A, ∠B, ∠C and ∠D are congruent to ∠E, ∠F, ∠G and ∠H respectively.
Thus Angle A is congruent To angle E.
Answer:
Angle E is congruent to angle A, So the required answer is E.
Step-by-step explanation:
If a figure dilated, then the image and pre-image are similar figures.
It is given that angle parallelogram ABCD is dilated to form parallelogram EFGH.
It means both parallelogram are similar.
[tex]ABCD\sim EFGH[/tex]
The corresponding angles of similar figure are same.
[tex]\angle A=\angle E[/tex]
[tex]\angle B=\angle F[/tex]
[tex]\angle C=\angle G[/tex]
[tex]\angle D=\angle H[/tex]
Therefore angle E is congruent to angle A. The required answer is E.
