Answer: The ball is travelling with a speed of 5.5 m/s after hitting the bottle.
Explanation:
To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
[tex]m_1,u_1\text{ and }v_1[/tex] are the mass, initial velocity and final velocity of ball.
[tex]m_2,u_2\text{ and }v_2[/tex] are the mass, initial velocity and final velocity of bottle.
We are given:
[tex]m_1=0.4kg\\u_1=18m/s\\v_1=?m/s\\m_2=0.2kg\\u_2=0m/s\\v_2=25m/s[/tex]
Putting values in above equation, we get:
[tex](0.4\times 18)+(0.2\times 0)=(0.4\times v_1)+(0.2\times 25)\\\\v_1=5.5m/s[/tex]
Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.
