Respuesta :

Answer:

[tex](3.2)[/tex]

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

[tex]M(\frac{x1+x2}{2} .\frac{y1+y2}{2})[/tex]

In this problem we have

[tex]P(-2,8), Q(8,-4)[/tex]

Substitutes the values in the formula

[tex]M(\frac{-2+8}{2} .\frac{8-4}{2})[/tex]

[tex]M(3.2)[/tex]

The coordinates of the midpoint of line PQ is [tex]\boxed{\left( {3,2} \right)}.[/tex]

Further explanation:

The formula for distance between the two points can be expressed as follows,

[tex]\boxed{{\text{Distance}} = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} }[/tex]

The formula for the coordinates of midpoint of two points can be expressed as follows,

[tex]\boxed{{\text{Coordinates of midpoint}} = \left( {\frac{{{x_1} + {x_2}}}{2},\frac{{{y_1} + {y_2}}}{2}} \right)}[/tex]

]

Explanation:

From the graph it has been observed the coordinate of point P is [tex]P\left( { - 2,8} \right)[/tex] and coordinate of point Q is [tex]Q\left( { 8, -4} \right).[/tex]

Consider the midpoint of side PQ as R.

Consider the midpoints of the side PQ as [tex]\left( {x,y} \right).[/tex]

The midpoint between the points [tex]\left( { - 2,8} \right)[/tex] and [tex]\left( { 8, -4} \right)[/tex] can be obtained as follows,

[tex]\begin{aligned}{\text{Coordinate of R}} &= \left( {\frac{{8 - 2}}{2},\frac{{8 - 4}}{2}} \right)\\\left( {x,y} \right) &= \left({\frac{6}{2},\frac{4}{2}} \right)\\\left( {x,y} \right)&= \left({3,2} \right)\\\end{aligned}[/tex]

The coordinates of the midpoint of line PQ is [tex]\boxed{\left( {3,2} \right)}.[/tex]

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Coordinate Geometry

Keywords: Midpoint, point P, point Q, distance formula, section formula, line, line segment, coordinate geometry, PQ, quadrants.