Respuesta :
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
There is a supply of 20% saline solution and a supply of 50% saline solution.
If a teacher wants to mix together to get 60 ml of 28% saline solution for an experiment.
We will use "Mixture Allegation" to find the quantity of each solution:
Ist type of solution II nd type of solution
20% 50%
28%
--------------------------------------------------------------------------------------
50%-28% : 28%-20%
22% : 8%
11 : 4
Since there is total quantity of 60 ml of solution.
So, Quantity of 20% solution in the mixture is given by
[tex]\frac{11}{15}\times 60=11\times 4=44\ ml[/tex]
Quantity of 50% solution in the mixture is given by
[tex]\frac{4}{15}\times 60=4\times 4=16\ ml[/tex]
Hence, there is 44 ml of the 20% solution and 16 ml of the 50% solution.
Therefore, Option 'B' is correct.
