contestada

What is the change in enthalpy of the following reaction?

2NaBr(aq) + PbCl2(aq) 2NaCl(aq) + PbBr2(aq)

Given:
NaCl: ∆H = -411 kJ
NaBr: ∆H = -360 kJ
PbCl2: ∆H = -359 kJ
PbBr2: ∆H = -277 kJ