If my attached image is correct, then based on my computation NT is equal to C. 12.05
S is the center of the circle. OM = 18.
Based on the attached image, I concluded the following facts: 1) RM is the diameter 2) OM = NM ; NM = 18 3) ST and SU are radii so ST = SU 4) Q is the midpoint of SU ; QU = 8 5) P is the midpoint of ST. PT = QU thus PT = 8 6) P is the midpoint of NM thus NP = 9
Points NPT creates a right triangle. NT is the hypotenuse. We will use the Pythagorean theorem to solve for NT.
