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a car has a initial velocity of 20 ms-1 for the first 4 second of its motion it accelerates at 2.5ms-2. for the next t seconds it travels at a constant velocity if vms-1 the car then decelerates to rest. find v

a car has a initial velocity of 20 ms1 for the first 4 second of its motion it accelerates at 25ms2 for the next t seconds it travels at a constant velocity if class=

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pstnonsonjoku

The velocity, vms-1 has a numerical value of 30 m/s from the information provided in the question.

Now we have to use the formula;

v = u + at

Where;

v = final velocity

u = initial velocity

a = acceleration

t = time taken

Given that;

v = ?

u =  20 ms-1

t = 4 s

a = 2.5ms-2

If we substitute the values;

v =  20 ms-1 + (2.5ms-2 × 4 s)

v = 30 m/s

Learn more about velocity: https://brainly.com/question/862972

Lanuel

The constant velocity (V) of the car as it decelerates to rest is 2.222 m/s.

Given the following data:

  • Initial velocity = 20 m/s
  • Initial time = 4 seconds
  • Acceleration = 2.5 [tex]m/s^2[/tex]
  • Total time = 40 seconds

To determine the constant velocity (V) of the car:

First of all, we would calculate the distance traveled by the car within the first 4 seconds of its motion by using the second equation of motion;

[tex]S = ut + \frac{1}{2} at^2\\\\S=20(4)+\frac{1}{2} \times 2.5 \times 4^2\\\\S=80+20[/tex]

S = 100 meters.

Next, we would calculate the distance traveled after the first 4 seconds of its motion by using the third equation of motion;

Note: Final velocity is equal to zero since the car decelerated to rest.

[tex]V^2 =u^2 -2aS\\\\0^2 =20^2-2(2.5)S\\\\5S=400\\\\S=\frac{400}{5}[/tex]

S = 80 meters.

Now, we can find the constant velocity (V) of the car:

Time = [tex]40-4=[/tex] 36 seconds.

[tex]Velocity = \frac{distance }{time} \\\\Velocity = \frac{80 }{36}[/tex]

Velocity = 2.222 m/s

Read more on velocity here: https://brainly.com/question/10545161

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