In order
to solve the problem, we should know the heat capacity of silver. Which is
equal to 0.240 J/g C
The formula:
H = mCpT
Where h
is the energy applied
M is the
mass
Cp is the
specific heat
T is the
change in temperature
125 J = (
29.3 g ) ( 0.240 J/g C)
T
Solve for
T
T = 17.78
degree C increase