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It takes a 50 N horizontal force to pull a 20 kg object along the ground at a constant velocity. What is the coefficient of kinetic friction?

Respuesta :

Lanuel

The coefficient of kinetic friction is equal to 0.255.

Given the following data:

  • Horizontal force = 50 Newton
  • Mass = 20 kg

To calculate the coefficient of kinetic friction:

Mathematically, the coefficient of kinetic friction is given by the formula;

[tex]F_k = umg[/tex]

Where;

  • Fk represents the force of kinetic friction.
  • μ represents the coefficient of kinetic friction.
  • m represents the mass.
  • g is the acceleration due to gravity.

Making u the subject of formula, we have:

[tex]u = \frac{F_k}{mg}[/tex]

Substituting the given parameters into the formula, we have;

[tex]u = \frac{50}{20 \times 9.8}\\\\u = \frac{50}{196}[/tex]

Coefficient of kinetic friction, u = 0.255.

Read more on coefficient of kinetic friction here: https://brainly.com/question/13940648

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