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A 0.0622 m solution of iron (III) chloride, FeCl3, in water freezes at –0.412°C. Determine the Van’t Hoff’s factor of FeCl3 in this solution.

Respuesta :

pstnonsonjoku

The Van't Hoff factor of the solution is  3.56.

We know that the formula for freezing point depression is;

ΔT = K m i

ΔT = freezing point depression

K = Freezing constant

m = molality of solution

i = Van't Hoff factor

ΔT = Freezing point of pure water - Freezing point of solution

Freezing point of pure water = 0°C

ΔT = 0°C - ( –0.412°C)

ΔT = 0.412°C

Now;

i = ΔT/K m

K = 1.86 °C/m for water

m =  0.0622 m

i =  0.412°C/ 1.86 °C/m ×  0.0622 m

i = 3.56

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