lorenzo reparte entre sus nietos 58 caramelos,de forma inversamente proporcional a sus edades,que son6,8 y9 años.¿cuantos le corresponderan a cada uno?

Respuesta :

Lanuel

The number of candies each of the grandchild would get is 24, 18 and 16 candies respectively.

Given the following data:

  • Total number of candies = 58 candies
  • Ages = 6, 8 and 9 years

To determine the number of candies each of the grandchild would get:

Note: The candies were distributed to the grandchildren inversely proportional to their ages.

Mathematically, this is given by this expression:

[tex]Candies \; \alpha\; \frac{1}{Age}[/tex]  ≡ [tex]C = \frac{k}{A}[/tex]

Thus, the above expression is re-written for all the grandchildren as follows:

[tex]58 = \frac{k}{6} + \frac{k}{8}+\frac{k}{9}[/tex]

Lowest common multiple (LCM) of 6, 8 and 9 is 72.

[tex]58=\frac{12k +8k+9k}{72} \\\\58=\frac{29k}{72}\\\\29k =72 \times 58\\\\29k =4176\\\\k=\frac{4176}{299}[/tex]

k = 144.

For the first grandchild:

[tex]Candy = \frac{k}{6} \\\\Candy = \frac{144}{6}[/tex]

Candy = 24 candies.

For the second grandchild:

[tex]Candy = \frac{k}{6} \\\\Candy = \frac{144}{8}[/tex]

Candy = 18 candies.

For the third grandchild:

[tex]Candy = \frac{k}{6} \\\\Candy = \frac{144}{9}[/tex]

Candy = 16 candies.

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