if Cadmium has an atomic number of 48 and an atomic mass of 112 and it undergoes alpha decay the element formed is palladium with atomic number of 46 and atomic mass of 108.
Alpha decay is the type of radioactive decay in which a nucleus emit alpha decay due to the change in the atomic nucleus, the element changes into another element.
Generally, the mass number is reduced by 4 and the atomic number is reduced by 2.
Therefore, if Cadmium has an atomic number of 48 and an atomic mass of 112 and it undergoes alpha decay, the new element produced can be represented as follows:
Cd¹¹²₄₈ → Pd¹⁰⁸₄₆ + He₂⁴
The atomic mass and atomic number of cadmium reduced by 4 and 2 respectively to form palladium with atomic mass of 108 and atomic number of 46.
Therefore, the element form is palladium with atomic number of 46 and atomic mass of 108.
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