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Which system of equations has a solution of (1,2,3)
ОА.
1 + y + 2z = 9
21 + 2y + 3z = 15
1 - 2 = -2
OB.
I + y = 3
y - 2 = 1
I + y + z = 0
Ос.
-21 - 2z = -8
y + 3z = 7
I + y - 3z = -3
D. -35 + 2y + z = 4
I-y + 2z = 5
s-y-2=-2
Please someone for the love of god help me!!!!!!

Respuesta :

cmorgan2468

Answer:

x = t

y = -t

z = (17-6t)/5

Step-by-step explanation:

First we will write down Equation 1 and Equation 2

4x-2y+5z = 17------(1)

x + y = 0--------(2)

Since we are asked to express our answer in terms of the parameter t so lets suppose x = t and  y = -t

Now substitute the value of x and y in equation (1) we get

4(t) -2(-t) +5z = 17

6t + 5z = 17

5z = 17 -6t

z = (17-6t)/5

hence we get the following answer

x = t

y = -t

z= (17-6t)/5

we can also verify our answer by substituting the values of x ,y and z in any of the two equations above, for example lets substitute these values in equation 1

4(t) -2(-t) + 5((17-6t)/5)) = 17

6t + 17 -6t = 17

6t -6t = 17 -17

0 = 0

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