Kaidled6206
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The equation of line m is: -2x + 5y = 10

What is the slope of a line perpendicular to line m?

Enter your answer as a fraction in the box.

Respuesta :

JeremiLovers08

Answer:

[tex] - 2x + 5y = 10 \\ 5y = 2x + 10 \\ \frac{5}{5} y = \frac{2}{5} x + \frac{10}{5} \\ \bf \: y = \frac{2}{5} x + 2[/tex]

m(gradient)=2/5
  • -2x+5y=10

Isolate y

[tex]\\ \sf\longmapsto 5y=2x+10[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{2}{5}x+2[/tex]

  • m=2/5

Now

  • Perpendicular line has slope negative reciprocal to it

[tex]\\ \sf\longmapsto m=-5/2[/tex]

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