The missing information in the proof is a
The complete question is to prove that:
[tex]DE = \frac 12BC[/tex]
Start by calculating the distance DE and BC using the following distance formula
[tex]d = \sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}[/tex]
So, we have:
[tex]BC = \sqrt{(0 -2a)^2 +(0-0)^2}[/tex]
[tex]BC = \sqrt{(-2a)^2 +0^2}[/tex]
Evaluate the exponents
[tex]BC = \sqrt{4a^2}[/tex]
[tex]BC = 2a[/tex]
Also, we have:
[tex]DE = \sqrt{(b -a - b)^2 +(c-c)^2}[/tex]
[tex]DE = \sqrt{(-a)^2 +0^2}[/tex]
Evaluate the exponents
[tex]DE = \sqrt{a^2 }[/tex]
[tex]DE = a[/tex]
The value of DE is calculated to be (a)
Hence, the missing information in the proof is a
Read more about midsegments at:
https://brainly.com/question/7423948
