Solution :
★ First answer :-
[tex]: \: \implies \: \sf{a \: + \: 2 \: = \: b}[/tex]
Transposing 2 to R.H.S. so it would be negative,
[tex] : \: \implies \: \boxed{\sf{a\: = \: b \: - \: 2}} \: \red\bigstar [/tex]
★ Second answer :-
[tex]: \: \implies \: \sf{3c \: = \: d}[/tex]
[tex]: \: \implies \: \boxed{\sf{c \: = \: \frac{d}{3} }} \: \red \bigstar[/tex]
★ Third answer :-
[tex]: \: \implies \: \sf{e \: - \: 5 \: = \: 2f}[/tex]
Transposing -5 from L.H.S. to R.H.S. it would be positive and become 5.
[tex]: \: \implies \: \boxed{\sf{e \: = \: 2f \: + 5}} \: \red \bigstar [/tex]
Hence solved..!!!
