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The number of ways six people can be placed in a line for a photo can be determined using the expression 6!. What is the value of 6!? Two of the six people are given responsibilities during the photo shoot. One person holds a sign and the other person points to the sign. The expression StartFraction 6 factorial Over (6 minus 2) factorial EndFraction represents the number of ways the two people can be chosen from the group of six. In how many ways can this happen? In the next photo, three of the people are asked to sit in front of the other people. The expression StartFraction 6 factorial Over (6 minus 3) factorial 3 factorial EndFraction represents the number of ways the group can be chosen. In how many ways can the group be chosen?.

Respuesta :

The expressions are illustrations of permutations

  • There are 720 ways to line for a photo
  • There are 30 ways to give responsibilities to two of the six people
  • There are 20 ways to give three people can be asked to sit in front

The first expression is given as: 6!

Using factorial formula, we have:

[tex]6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1[/tex]

Multiply the factors

[tex]6! = 720[/tex]

This means that, there are 720 ways to line for a photo

The next expression is given as:

[tex]\frac{6!}{(6 - 2)!}[/tex]

Rewrite as:

[tex]\frac{6!}{(6 - 2)!} =\frac{6!}{4!}[/tex]

Expand

[tex]\frac{6!}{(6 - 2)!} =\frac{6 \times 5 \times 4!}{4!}[/tex]

Divide the common factors

[tex]\frac{6!}{(6 - 2)!} =6 \times 5[/tex]

Multiply

[tex]\frac{6!}{(6 - 2)!} = 30[/tex]

This means that, there are 30 ways to give responsibilities to two of the six people

The next expression is given as:

[tex]\frac{6!}{(6 - 3)!3!}[/tex]

Rewrite as:

[tex]\frac{6!}{(6 - 3)!3!} = \frac{6!}{3!3!}[/tex]

Expand

[tex]\frac{6!}{(6 - 3)!3!} = \frac{6 \times 5 \times 4 \times 3!}{3!\times 3 \times 2 \times 1}[/tex]

Divide the common factors

[tex]\frac{6!}{(6 - 3)!3!} = \frac{6 \times 5 \times 4}{ 3 \times 2 \times 1}[/tex]

[tex]\frac{6!}{(6 - 3)!3!} = \frac{120}{6}[/tex]

Divide

[tex]\frac{6!}{(6 - 3)!3!} = 20[/tex]

This means that, there are 20 ways to give three people can be asked to sit in front

Read more about permutations at:

https://brainly.com/question/8119212

Answer:

720,30,20

Explanation: