[tex]\huge \dag \sf{Answer \: it}[/tex]​

[tex]f = g \times \frac{m _{1}m_{2}}{ {d}^{2} } [/tex]
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Respuesta :

Answer:

Hey There!

Let's solve ....

[tex]let \: m_{1} \: and \: m_{2} \: are \: the \: two \\ masses \: seperated \: by \: \\ distance \: d \\ \\ lets \: find \: equation \: 1 \\ \\ f \propto m_{1} m_{2} \\ \\ now \: equation \: 2 \\ \\ f \propto \frac{1}{ {d}^{2} } [/tex]

On combining these two equations, it comes

[tex]f \propto \frac{ m_{1} m_{2} }{ {d}^{2} } \\ \\ f = g \times \frac{ m_{1} m_{2} }{ {d}^{2} } \\ \\ [/tex]

[G is a gravitational constant here]...

Hence it is proved.

I hope it is helpful to you..

Cheers!_________