[tex] \sqrt{ - 1 - 2n} = n \\ = > ( \sqrt{ - 1 - 2n )} ^{2} = {n}^{2} \\ = > - 1 - 2n = {n}^{2} \\ = > {n}^{2} + 2n + 1 = 0 \\ = > {(n)}^{2} + 2 \times n \times 1 + {(1) }^{2} = 0 \\ > {(n + 1)}^{2} = 0 \\ = > n + 1 = 0 \\ = > n = - 1[/tex]
Answer:
n = -1
Hope you could get an idea from here.
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