kennagund25
contestada

A compound with a molar mass of
312.2 g/mol contains 69.23% C, 3.85% H, and
26.92% N. What is the molecular formula of
this compound?

Respuesta :

onyebuchinnaji

The molecular formula of the compound is [tex]C_1_8H_1_2N_6[/tex].

The given parameters:

  • Molar mass of the compound, = 312.2 g/mol
  • Composition of the compound, C = 69.23%, H = 3.85%, N = 26.92%

The empirical formula of the compound is calculated as follows;

[tex]= \frac{69.23}{C} , \ \ \frac{3.85}{H}, \ \ \frac{26.92}{N} \\\\= \frac{69.23}{12} , \ \ \frac{3.85}{1} , \ \ \frac{26.92}{14} \\\\= 5.77 , \ \ 3.85, \ \ 1.92\\\\= \frac{5.77}{1.92} , \ \ \frac{3.85}{1.92} , \ \ \frac{1.92}{1.92} \\\\= 3, \ \ 2, \ \ 1\\\\empirical \ formula = C_3H_2 N[/tex]

The molecular formula of the compound is calculated as follows;

[tex](C_3H_2N) n = 312.2 \ g/mol\\\\(12\times 3\ \ + \ 1 \times 2\ \ + \ 14) n = 312.2\\\\(52)n = 312.2\\\\n = \frac{312.2}{52} \\\\n = 6\\\\molecular \ formula = (C_3H_2N)n = (C_3H_2N)6= C_1_8H_1_2N_6[/tex]

Thus, the molecular formula of the compound is [tex]C_1_8H_1_2N_6[/tex].

Learn more about empirical and molecular formula here: https://brainly.com/question/821180

Otras preguntas