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7. Find the equation of the line that passes through each of the following pairs of points in y = mx + b form.
(a) (1,7) and (4,22)
(b) (-2,13) and (2,3)
(c) (4,6) and (10,0)
I
(d) (0, -10) and (16, 2)

Respuesta :

Considering the expression of a line, you obtain:

(a) the equation of the line that passes through the pair of points (1,7) and (4,22) is y=5x + 2.

(b) the equation of the line that passes through the pair of points (-2,13) and (2,3) is y=-2.5x + 8.

(c) the equation of the line that passes through the pair of points (4,6) and (10,0) is y=-1x + 10.

(d) the equation of the line that passes through the pair of points (0, -10) and (16, 2) is y= 0.75x - 10.

A linear equation o line can be expressed in the form y = mx + b.

where

  • x and y are coordinates of a point.
  • m is the slope.
  • b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

Knowing two points (x1, y1) and (x2, y2) of a line, the slope m of said line can be calculated using the following expression:

[tex]m=\frac{y2 -y1}{x2 -x1}[/tex]

Substituting the value of the slope m and the value of one of the points in the expression of a linear equation, y = mx + b, the value of the ordinate to the origin b can be obtained.

So, in this case, you can calculated in this case:

(a) Being (x1,y1)= (1,7) and (x2,y2)= (4,22), the slope m can be calculated as:

[tex]m=\frac{22 -7}{4 -1}[/tex]

m= 5

Considering point 1 and the slope m, you obtain:

7= 5×1 + b

7= 5 +b

7-5= b

2=b

Finally, the equation of the line that passes through the pair of points (1,7) and (4,22) is y=5x + 2.

(b) Being (x1,y1)= (-2,13) and (x2,y2)= (2,3), the slope m can be calculated as:

[tex]m=\frac{3 -13}{2 -(-2)}[/tex]

m= -2.5

Considering point 2 and the slope m, you obtain:

3= -2.5×2 + b

3= -5 +b

3+5= b

8=b

Finally, the equation of the line that passes through the pair of points (-2,13) and (2,3) is y=-2.5x + 8.

(c) Being (x1,y1)= (4,6) and (x2,y2)= (10,0) , the slope m can be calculated as:

[tex]m=\frac{0 -6}{10 -4}[/tex]

m= -1

Considering point 1 and the slope m, you obtain:

6= -1×4 + b

6= -4 +b

6+4= b

10=b

Finally, the equation of the line that passes through the pair of points (4,6) and (10,0) is y=-1x + 10.

(d) Being (x1,y1)= (0,-10) and (x2,y2)= (16,2) , the slope m can be calculated as:

[tex]m=\frac{2 -(-10)}{16 -0}[/tex]

m= 0.75

Considering point 2 and the slope m, you obtain:

2= 0.75×16 + b

2= 12 +b

2-12= b

-10=b

Finally, the equation of the line that passes through the pair of points (4,6) and (10,0) is y= 0.75x - 10.

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