contestada

The combustion of glucose, C6 H12 O6 (s), produces carbon dioxide, CO2 (g), and water, H2 O(g), according to the equation below. Upper C subscript 6 upper H subscript 12 upper O subscript 6 (s) plus 6 upper O subscript 2 (g) right arrow 6 upper C upper O subscript 2 (g) plus 6 upper H subscript 2 upper O (l). The enthalpy of the reaction is â€"2,840 kJ. What is the heat of combustion, per mole, of glucose? â€"2,840 kJ/mol â€"473. 3 kJ/mol 473. 3 kJ/mol 2,840 kJ/mol.

Respuesta :

pstnonsonjoku

The heat of combustion, per mole, of glucose is -2,840 kJ/mol.

The proper equation for the combustion of glucose is shown as follows;

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g)

The heat of combustion is the heat released when the substance is burnt under standard conditions.

From the question, the enthalpy of combustion of glucose is -2,840 kJ. Let us recall that the equation shows the heat required to burn 1 mole of glucose. Hence, the heat of combustion, per mole, of glucose is -2,840 kJ/mol.

Learn more about heat of combustion: https://brainly.com/question/6817761

whitenb

Answer:

A  

Explanation:

EDGE 2022

Otras preguntas