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Example:
was with a mass of 1500 kg accelerates from 0 to 27.78 mis at 5.20 ms' The frictional force on the car
700 N Calculate the power of the engine (1.18 x 10"Wer 118 kW)

Respuesta :

onyebuchinnaji

The instantaneous power of the engine of the car is 121 kW.

The given parameters:

  • Mass, m = 1500 kg
  • Initial velocity, u = 0
  • Final velocity, v = 27.78 m/s
  • Time of motion, t = 5.2 s
  • Frictional force on the car, F = 700 N

The force exerted by the car is calculated as follows;

[tex]F = \frac{m(v- u)}{t} \\\\F = \frac{1500(27.78-0)}{5.2 } \\\\F = 8013.46 \ N[/tex]

The total force exerted on the engine is calculated as follows;

[tex]F= 8013.5 \ N + \ 700 \ N\\\\ F = 8713.46 \ N[/tex]

The instantaneous power of the engine is calculated as follows;

[tex]P = F\bar v\\\\P = F \times (\frac{v-u}{2} )\\\\P = 8713.46 \times (\frac{27.78 -0}{2} )\\\\P = 1.21 \times 10^5 \ W\\\\P = 121 \ kW[/tex]

Thus, the instantaneous power of the engine of the car is 121 kW.

Learn more about instantaneous power here: https://brainly.com/question/8893970

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