Please Help! In which of the following intervals does the trigonometric inequality sec(x)
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Step-by-step explanation:
sec(x) = 1/cos(x)
cot(x) = cos(x)/sin(x)
sec is smaller than cot, if cos is negative (making sec negative) and sin is negative (making cot positive).
and that is true for the third quadrant.
which is pi < x < 3×pi/2
so, the third answer is right.