A group of college students built a self-guided rover and tested it on a plane surface. They programmed the vehicle to move along the path Aâ€""Bâ€""Câ€""Dâ€""A represented on the coordinate plane. What distance will the rover cover if it completes one circuit?.

Respuesta :

The distance covered by the rover is the perimeter of the trapezoid, and it is 40 meters.

See attachment for the path followed by the rover.

From the attached graph, we have the following lengths

[tex]AD = 9m[/tex]

[tex]AB = 2m[/tex]

[tex]DC = 14m[/tex]

Next, we calculate the distance BC using the following Pythagoras theorem

[tex]BC^2 = AD^2 + x^2[/tex]

Where:

[tex]x = 12[/tex]

So, we have:

[tex]BC^2 = 9^2 + 12^2[/tex]

[tex]BC^2 = 225[/tex]

Take positive square root of both sides

[tex]BC = 15[/tex]

The distance covered is the sum of the side lengths of the trapezoid.

So, we have:

[tex]Distance =AD + AB +DC + BC[/tex]

This gives

[tex]Distance =9m+ 2m +14m + 15m[/tex]

Add the lengths

[tex]Distance =40m[/tex]

Hence, the distance covered by the rover is 40 meters

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Ver imagen MrRoyal